So, you may know I want to create an interactive show where the audience will choose the character's destiny.
The audience would be presented with scenarios and options to choose from to advance the story.
The story will change with each choice. Yet it will be linear.
It's looks a little bit like this:
1)
So, from left to right.
The story is happening going along a linear path...
Oh no! An event of decision occurred!
The audience must choose between A or B...
2)
The audience chose option A.
The narrative branches out to acknowledge the choice made - different to that of option B - before resolving into a linear narrative before the next event.
3)
Another choice!
This time the audience choose B, and the story branches in the opposite direction to A this time...
4)
Because the audience chose A twice, and B once, ending A will occur.
The audience get ending A!
This is a simplistic structure I have tested a few times now. In Algora, and Shadows of Algora (both 2014), the audience had 3 options to choose from.
In order for a conclusive ending, the amount of choices at the very least must be one greater than the number of options within a choice.
To elaborate.
2 options = 3 choices or 2 options = 5 choices or 2 options = 7 choices
3 options = 4 choices or 3 options = 6 choices or 3 options = 8 choices
4 options = 5 choices or 4 options = 7 choices or 4 options = 9 choices
Thank you for reading,
If you have any thoughts, do the thing!
Happy long weekend,
Kenneth :)
The story is happening going along a linear path...
Oh no! An event of decision occurred!
The audience must choose between A or B...
2)
The narrative branches out to acknowledge the choice made - different to that of option B - before resolving into a linear narrative before the next event.
3)
This time the audience choose B, and the story branches in the opposite direction to A this time...
4)
Another choice! The audience chose A this time.
All the choices have been made, time to count them.
5)
The audience get ending A!
This is a simplistic structure I have tested a few times now. In Algora, and Shadows of Algora (both 2014), the audience had 3 options to choose from.
In order for a conclusive ending, the amount of choices at the very least must be one greater than the number of options within a choice.
To elaborate.
2 options = 3 choices or 2 options = 5 choices or 2 options = 7 choices
3 options = 4 choices or 3 options = 6 choices or 3 options = 8 choices
4 options = 5 choices or 4 options = 7 choices or 4 options = 9 choices
Thank you for reading,
If you have any thoughts, do the thing!
Happy long weekend,
Kenneth :)





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